janet built a 5-inch ny 7-inch rectangle
A:what is the perimeter of janets rectangle?
B:the perimeter of olivia's rectangle is 150% as long as janet's. what is the perimeter of olivia's rectangle?
C. what is the area of janets rectangle?
D.the area of walters rectangle is 6/5 the area of janets. what is the area of walters rectanglr?
A.
P = 2L + 2W
P = 2(5) + 2 (7)
P = 24 inches
B. 1.5 * 24 = ?
I'll be glad to check your answers for the other two problems.
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To find the perimeter of a rectangle, you need to add up the lengths of all four sides. In this case, Janet's rectangle has dimensions of 5 inches by 7 inches.
A: To find the perimeter of Janet's rectangle, you need to add up the lengths of all four sides. In this case, the lengths of two opposite sides are 5 inches each, and the lengths of the other two opposite sides are 7 inches each. So, the perimeter is:
Perimeter of Janet's rectangle = 5 + 5 + 7 + 7 = 24 inches
B: To find the perimeter of Olivia's rectangle, which is 150% longer than Janet's, you first need to calculate 150% of the perimeter of Janet's rectangle and then add it to the original perimeter.
Perimeter of Olivia's rectangle = (150/100) * (Perimeter of Janet's rectangle) + Perimeter of Janet's rectangle
Since the perimeter of Janet's rectangle is 24 inches, you can plug this value into the formula:
Perimeter of Olivia's rectangle = (150/100) * 24 + 24 = 36 + 24 = 60 inches
C: The area of a rectangle is found by multiplying its length by its width. In this case, Janet's rectangle has dimensions of 5 inches by 7 inches.
Area of Janet's rectangle = Length * Width = 5 inches * 7 inches = 35 square inches
D: To find the area of Walter's rectangle, which is 6/5 times the area of Janet's rectangle, multiply the area of Janet's rectangle by 6/5.
Area of Walter's rectangle = 6/5 * (Area of Janet's rectangle) = 6/5 * 35 = 42 square inches
I hope this helps!