if a student used 12.45mL of their NaOH solution to neutralize 10.00mL of a 0.543 KHP solution, then what is the concentration of the student's NaOH solution?
KHP + NaOH ==> NaKP + H2O
mols KHP = grams/molar mass
From the equation, mols KHP = mols NaOH.
M NaOH = moles NaOH/L NaOH
To find the concentration of the student's NaOH solution, we can use the equation:
C1V1 = C2V2
Where:
C1 = concentration of NaOH solution (unknown)
V1 = volume of NaOH solution used (12.45 mL)
C2 = concentration of KHP solution (0.543 M, assuming Molarity)
V2 = volume of KHP solution used (10.00 mL)
Let's substitute the values into the equation:
C1 * 12.45 mL = 0.543 M * 10.00 mL
Now we can solve for C1 (the concentration of the NaOH solution):
C1 = (0.543 M * 10.00 mL) / 12.45 mL
C1 = 0.437 M
Therefore, the concentration of the student's NaOH solution is 0.437 M.