A ball is thrown with a speed of 100m/s attains a height of 150m.Calculate <a>the time of flight the angle of projection

NONSO should try to reexplain

Well

Time of flight:

That would be twice the time it takes the ball to fall H = 150 m, which is
t = 2*sqrt(2H/g) = 11.07 s
(You double the fall time to get the total time of flight)

Launch angle:
V*sinA/g = t/2 = 5.533 s
sin A = 0.5422
A = 32.8 degrees

Range:
(Vo^2/g)*sin(2A) = 930 m

Note: No human being can throw a ball that fast, or that far. It would be 224 miles per hour

Ok, tnx

Height of 100m and speed of 50ms-1?calcuate.the angle of projection?

To find time of flight t=2u sin ₹/g

15.44sec

I need the procedure on how to solve the question

But they gave answers to b <a>15.49s 50.70degree

Those are my final answers.