2x+3y=3
3y=5-2x
4x-y=3
4x=y=1
solve and explain please
They cannot be solved. Add 2x to both sides of the second equation in the pair to see this.
You have a typo in the last equation. If it is -y, then they are unsolvable. If positive y, then add the two equations to get 8x = 4 or x = 4/8 = 1/2
It would help if you proofread your questions before you posted them.
4x-y=3
4x+y=1
sorry
and show work
To solve the system of equations, we'll use the method of substitution:
Step 1: Solve one of the equations for one variable in terms of the other variable. Let's solve the second equation for y:
3y = 5 - 2x
Divide both sides of the equation by 3:
y = (5 - 2x) / 3
Step 2: Substitute the expression for y in terms of x into the first equation:
2x + 3y = 3
2x + 3((5 - 2x) / 3) = 3
Simplify:
2x + (5 - 2x) = 3
Step 3: Combine like terms:
2x - 2x + 5 = 3
5 = 3
Step 4: Since the equation 5 = 3 is not true, it means the system of equations is inconsistent. In this case, there is no solution that satisfies both equations simultaneously.
Therefore, the system of equations is inconsistent and does not have a solution.