The perimeter of a rectangle is to be no greater than 300 in., and the length must be 125 in. Find the maximum width of the rectangle.
you have 2 lengths of 125, so you use up 250. Now you have 50 left, the 2 other sides must be even in order to be a rectangle. So divide 50 by 2 and you get 25. Therefore the rectangles sides are 125,125, 25,2.
But maybe use algebra. I do not know what math carly is taking.
2 L + 2 W </= 300
250 + 2 W </= 300
2 W </= 50
W </= 25
56>[=2
To find the maximum width of the rectangle, we need to use the given information and apply it to the formula for the perimeter of a rectangle.
Let's start by understanding the formula for the perimeter of a rectangle:
Perimeter = 2*(Length + Width)
We are given that the length of the rectangle is 125 inches, so we can substitute this value into the formula:
Perimeter = 2*(125 + Width)
Now we know that the perimeter must be no greater than 300 inches, so we can set up an inequality:
2*(125 + Width) ≤ 300
To find the maximum width, we need to solve this inequality by isolating the width variable.
Let's solve the inequality step by step:
2*(125 + Width) ≤ 300
First, distribute the 2:
250 + 2*Width ≤ 300
Then, subtract 250 from both sides:
2*Width ≤ 300 - 250
2*Width ≤ 50
Next, divide both sides by 2:
Width ≤ 50/2
Now we find:
Width ≤ 25
Therefore, the maximum width of the rectangle is 25 inches.