a certain center uses both form and form b if form a is used 4 times more than form b and in the course of one day they use form a and b 750 times how many times was form a used
b + 4b = 750
5b = 750
b = 750 / 5
b = 150
208 times 2
b + 4b = 750
5b=750
5b/5 =750/5=b=150
4*150=600
Form a is used 600 times
Form b is used 150 times
To solve this problem, let's set up an equation.
Let's assume that the number of times form B is used is represented by the variable "x".
Given that form A is used 4 times more than form B, we can express the number of times form A is used as 4x.
We are also given that the total number of times form A and B are used in one day is 750.
So, we can create the equation:
4x + x = 750
Combining like terms, we get:
5x = 750
To solve for x, we divide both sides of the equation by 5:
x = 750/5
Simplifying, we find:
x = 150
Therefore, form B is used 150 times.
To find the number of times form A is used, we can substitute this value back into our equation:
4x = 4 * 150
Simplifying, we find:
4x = 600
Therefore, form A is used 600 times.