A runner dashes from the starting line (x = 0) to a point 91 m away and then turns around and runs to a point 30 m away from the starting point in 25 seconds. To the nearest tenth of a m/s what is the average speed?
V = d/t = (91 + (91-30)) / 25 =
6.08
To find the average speed, we need to calculate the total distance traveled divided by the total time taken.
First, let's calculate the total distance traveled. The runner initially runs from the starting line to a point 91 m away, then turns around and runs back to a point 30 m away from the starting point. So the total distance traveled is the sum of these two distances: 91 m + 30 m = 121 m.
Next, we need to calculate the total time taken. The runner spends 25 seconds running from the starting line to the point 30 m away. Since this time is not mentioned in the context of the initial dash to the point 91 m away, we assume it's negligible and only consider the 25 seconds. Therefore, the total time taken is 25 seconds.
Now, we can find the average speed by dividing the total distance traveled by the total time taken:
Average Speed = Total Distance Traveled / Total Time Taken
Average Speed = 121 m / 25 s
Using a calculator, we can evaluate this: 121 / 25 = 4.84 m/s.
Therefore, the average speed to the nearest tenth of a m/s is approximately 4.8 m/s.