Please help! it has to do with momentum
A 70 k/g woman and her 35 k/g son are standing at rest on an ice rink. They push against each other for .60 s, causing them to glide apart. The speed of the woman immediately after they separate is .55 m/s
Mass units should be written as kg, not k/g.
You have not asked a question. You have only stated known physical conditions.
After pushoff, in order to maintain zero total momentum, the son's velocity must be twice that of the mother, 1.10 m/s
The momentum given to each skater, individually, is
70 * 0.55 = 38.5 kg*m/s
Divide that by 0.60 s if you want the force that they exert in each other during pushoff.
To solve this problem, we can use the principle of conservation of momentum. The total momentum of a closed system remains constant before and after the interaction.
Let's assume that the woman moves to the right (positive direction) with a velocity of v1 after the separation, and the son moves to the left (negative direction) with a velocity of v2.
Momentum is defined as the product of mass and velocity: p = m * v
According to the principle of conservation of momentum, the total momentum before the separation should be equal to the total momentum after the separation:
(mass of woman * initial velocity of woman) + (mass of son * initial velocity of son) = (mass of woman * final velocity of woman) + (mass of son * final velocity of son)
Substituting the given values:
(70 kg * 0 m/s) + (35 kg * 0 m/s) = (70 kg * 0.55 m/s) + (35 kg * v2)
Simplifying the equation:
0 = 38.5 kg m/s + 35 kg * v2
Rearranging the equation to solve for v2:
v2 = -38.5 kg m/s / 35 kg
v2 = -1.1 m/s
Therefore, the son moves to the left with a velocity of -1.1 m/s after they separate.