1280v^9y^5/
100v^4y3
Simplify by removing the factor of 1.
Do I look forthe commom multiple or no? Do I factor out again and then cancel off?
Use the denominator 100v^4y3 as a factor of the numerator. The fraction can be written
(100v^4y^3)*(128v^58y^2)/(100v^4y^3)
Now divide by and cancel out the denominator.
128v^54y-1/10v^4y^3???
To simplify the expression (1280v^9y^5)/(100v^4y^3) by removing the factor of 1, we can follow these steps:
1. Firstly, rewrite the expression as a division problem:
(1280v^9y^5) ÷ (100v^4y^3).
2. To remove the factor of 1, we need to find the greatest common factor (GCF) of the numerator and the denominator. Here, the GCF of the coefficients is 10, and the GCF of the variables is v^4y^3.
3. Now, divide both the numerator and the denominator by the GCF:
(1280 ÷ 10) * (v^9 ÷ v^4) * (y^5 ÷ y^3).
4. Simplify each part separately:
(128 ÷ 1) * (v^5) * (y^2).
5. Finally, combine all the simplified parts:
128v^5y^2.
So, the simplified form of (1280v^9y^5)/(100v^4y^3) after removing the factor of 1 is 128v^5y^2.