How much heat is lost by 65g of silver when it cools from 325ºC to -25ºC? (the specific heat of Ag(s) is 0.24 J/g ºC)
q lost = mass x specific heat x delta T.
546.0 J
To calculate the amount of heat lost by the silver, you need to use the formula:
Q = m * c * ΔT
Where:
Q = amount of heat lost (in joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in J/g ºC)
ΔT = change in temperature (in ºC)
Given values:
m = 65g
c = 0.24 J/g ºC
ΔT = final temperature - initial temperature
ΔT = -25ºC - 325ºC
= -350ºC
Now, substitute the given values into the formula:
Q = 65g * 0.24 J/g ºC * -350ºC
Performing the calculation:
Q = -5460 J
Therefore, 65g of silver will lose 5460 joules of heat when it cools from 325ºC to -25ºC.