A 5.0 MULTIPLIED BY 10 TO THE POWER OF 2g aluminium block is heated to 350 degrees celcius. determine the number of kilograms of ice at 0 degrees celcius that the aluminium block will melt as it cools.
How much heat is availbale in the Al block when changing T from 350 degrees Celsius (note the correct spelling of Celsius) to 0 degrees C.?
q = mass x specific heat Al x delta T.
how much heat is used in melting ice?
q = mass x heat fusion.
calculate mass.
Post your work if you get stuck.
To determine the number of kilograms of ice that the aluminum block will melt as it cools, we need to use the specific heat and heat of fusion equations. Here are the steps to calculate it:
Step 1: Convert the temperature from Celsius to Kelvin.
• Add 273 to the temperature in degrees Celsius to get the temperature in Kelvin.
• In this case, 350 degrees Celsius + 273 = 623 Kelvin.
Step 2: Calculate the amount of heat gained or lost by the aluminum block.
• Use the specific heat equation:
Q = mcΔT
where Q is the heat gained or lost, m is the mass, c is the specific heat, and ΔT is the change in temperature.
• The specific heat of aluminum is approximately 0.897 J/g°C.
• The mass of the aluminum block is given as 5.0 multiplied by 10^2g, which is 500 grams.
• ΔT is the change in temperature, so it is the final temperature minus the initial temperature. In this case, ΔT = 623 K - 273 K = 350 K.
• Substitute the values into the equation:
Q = (500 g) * (0.897 J/g°C) * (350 K - 273 K)
Step 3: Calculate the amount of ice melted.
• Use the heat of fusion equation:
Q = mL
where Q is the heat gained or lost, m is the mass, and L is the heat of fusion.
• The heat of fusion for ice is approximately 334 J/g.
• We want to find the mass of ice (m), so rearrange the equation:
m = Q / L
• Substitute the values from Step 2:
m = [(500 g) * (0.897 J/g°C) * (350 K - 273 K)] / 334 J/g
Step 4: Convert the mass of ice to kilograms.
• Divide the mass of ice by 1000 to convert it from grams to kilograms.
By following these steps and performing the calculations, you can determine the number of kilograms of ice that the aluminum block will melt as it cools.