2cosx + sqr3 = x [0degrees,360degrees)
2 cosx + √3 = x
tough equation to solve.
We could use Newton's Method in Calculus, but I don't know at what level this is
I plotted y = 2cos(x) + 3^.5 and y = x on
http://rechneronline.de/function-graphs/
and it looks like there is one solution at appr. 1.6 or 1.7
Or you could do this ...
set your calculator to radians
x ---LS
1.6 1.67
1.62 1.63
1.625 1.624
so x = appr. 1.625
If you want this to be in degrees, the equation would become
2cos(180*x/3.1415926) + √3 = x
I at appr. 3.7°
LS = cos 3.7° + √3 = 3.728
RS = 3.7
x = 3.73 , LS = 3.728
not bad