A car starts from rest and reaches a velocity of 8 m/s in 4 seconds.
a) What is its acceleration?
b)If its acceleration remains the same, what will be its velocity in 15 seconds? plsss helpp meeeeeeeeeeeeeeeeeeeeeee
acceleration= changevelocity/time=8/4 m/s^2
v(15)= acceleration*15
a) To find the acceleration, we can use the formula:
acceleration = change in velocity / time
Since the car starts from rest, its initial velocity (u) is 0 m/s, and its final velocity (v) is 8 m/s. The time taken (t) is 4 seconds.
So, the acceleration is:
acceleration = (8 m/s - 0 m/s) / 4 s
acceleration = 8 / 4
acceleration = 2 m/s²
Therefore, the acceleration of the car is 2 m/s².
b) To find the velocity after 15 seconds, we can use the formula for constant acceleration:
velocity = initial velocity + (acceleration * time)
In this case, the initial velocity (u) is 0 m/s, the acceleration is 2 m/s², and the time (t) is 15 seconds.
So, the velocity after 15 seconds is:
velocity = 0 m/s + (2 m/s² * 15 s)
velocity = 30 m/s
Therefore, if the acceleration remains constant, the velocity of the car after 15 seconds would be 30 m/s.