Calculus

At noon, ship A is 180 km west of ship B. Ship A is sailing east at 40 km/h and ship B is sailing north at 30 km/h. How fast is the distance between the ships changing at 4:00 PM?

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  1. draw the right triangle.

    start the origin at B at noon.

    a is the distance ship A moves in 4 hours.

    a= -180+40*4=-20km
    da/dt= + 40

    b is the distance from the B starting point at noon.
    b= 30*4=120
    db/dt=30\
    r=sqrt(a^2+b^2)
    dr/dt= 1/2 *1/(a^2+b^2)* (2a da/dt+2b db/dt)

    solve for dr/dt

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    bobpursley
  2. I tried plugging in the numbers for the variables, but I am not coming up with the right answer. I think the equation might be wrong.

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