Find the integral of (3x-2)4^x dx
A couple of hints should get you going on the right track:
Int(x e^x) = e^x(x-1)
4 = e^(ln 4), so 4^x = e^(ln 4 * x)
Now it's just plug and chug.
Int(x e^x) = e^x(x-1)
4 = e^(ln 4), so 4^x = e^(ln 4 * x)
Now it's just plug and chug.