CHEMISTRY

90.0 of is initially at room temperature (22.0). A chilled steel rod at 2.0 is placed in the water. If the final temperature of the system is 21.3, what is the mass of the steel bar?
Specific heat of water = 4.18

Specific heat of steel = 0.452

1. The sume of the heats gained is zero (some heats gained are negative). Because I cannot read the units above,

masswater*cw*(21.3-22)+masssteel*csteel*(21.3-2)=0
solve for mass steel

posted by bobpursley

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