subtract write i simplest form
7/y-8 - 1/y+1
MULIPLY
-3a^b/35a^5 TIMES 14a^3b^2/-9b^4
did you mean
7/(y-8) - 1/(y+1)
or did you want it done the way you wrote it
there is a tremendous difference
To subtract the given expression and write it in simplest form, we need to find a common denominator for the two fractions.
The common denominator is the least common multiple (LCM) of the denominators, which in this case is (y - 8)(y + 1).
Let's rewrite the expression using the common denominator:
7/(y - 8) - 1/(y + 1)
To do this, multiply the numerator and denominator of the first fraction by (y + 1) and multiply the numerator and denominator of the second fraction by (y - 8):
(7 * (y + 1)) / ((y - 8)(y + 1)) - (1 * (y - 8)) / ((y - 8)(y + 1))
Simplifying further, we get:
(7y + 7) / ((y - 8)(y + 1)) - (y - 8) / ((y - 8)(y + 1))
Now, we can bring both fractions to a common denominator:
(7y + 7 - (y - 8)) / ((y - 8)(y + 1))
Simplifying the numerator:
(7y + 7 - y + 8) / ((y - 8)(y + 1))
Combining like terms:
(6y + 15) / ((y - 8)(y + 1))
Therefore, the simplified form of the given expression is (6y + 15) / ((y - 8)(y + 1)).