For a chemistry lab the experiment was to carry out an acid-base titration to determine the exact concentration of a sodium hydroxide solution.
Two trials were completed and the data collected was: mass of weighing paper, mass of weighing paper + KHP, mass of KHP, initial buret reading, final buret reading, and volume of NaOH.
The molecular weight of KHP is 204.44 grams/mol.
I need to find the number of moles of KHP, the number of moles of NaOH and the concentration of NaOH but i am not sure how to do this. Please help,thank you!!
I know that these questions were already answered but I wanted to see if my calculations were correct.
For my first trial KHP was 1.00g and for the second trial it was the same. So to fin moles of KHP i need to do grams/molar mass so would it be
204.44 g/mol X 1/1g = 204.44 g/mol?
I shall be glad to check your results; however, you provided only the mass of the KHP. I need the volume of the NaOH solution used if you want the molarity of the NaoH.
For the 1.00 g KHP, yes, moles KHP = 1.00/204.44 = ? but you did not do that correctly.
It is 1.00g KPH x (1 mol KHP/204.44g) = ? moles KHP.
ok so for mole of kHP it would be 1/204.44 = 0.00489 g/mol?
The volume of NaOH for trial 1 was 14.50 mL and for trial 2 it was 9.90mL.
So would it be 39.998 which is molecular mass of NaOH divided by the volume?
welldone Hannah xx your doing great! xxx keep up the hard work xoxo :*
To find the number of moles of KHP, you are correct in using the formula grams/molar mass. However, you made a slight error in your calculation. Let's go through the correct calculation:
For the first trial, the mass of KHP is 1.00g. The molar mass of KHP is 204.44 g/mol. So the number of moles of KHP can be calculated as:
Number of moles of KHP = mass of KHP / molar mass of KHP
= 1.00g / 204.44 g/mol
= 0.00489 mol
Similarly, for the second trial where the mass of KHP is also 1.00g, the number of moles of KHP would be the same:
Number of moles of KHP = 1.00g / 204.44 g/mol
= 0.00489 mol
So, the correct number of moles of KHP for both trials is 0.00489 mol.
Now, let's move on to finding the number of moles of NaOH and the concentration of NaOH.
To find the number of moles of NaOH, we can use the balanced chemical equation between NaOH and KHP, which should have been provided in the question or lab instructions. Without the equation, it is not possible to determine this information.
Once you have the balanced equation, you can use stoichiometry to find the number of moles of NaOH based on the number of moles of KHP used in the titration.
Finally, to calculate the concentration of NaOH, you need to divide the number of moles of NaOH by the volume of NaOH used in the titration. The units of concentration would depend on the units of volume used (e.g., Molarity if volume is given in liters).
Remember to always include the units in your calculations to ensure accurate results.