math

Please explain the steps on to solve this equation.

x^-6 - 8x^-3 + 16 = 0

k^-4/3 - 10k^-2/3 + 21 = 0

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  1. x^-6 - 8x^-3 + 16 = 0

    Put x^(-3) = y. Then:

    y^2 - 8 y + 16 = 0 --->

    (y - 4)^2 = 0 --->

    y = 4 ---->

    x = 4^(-1/3) = 2^(-2/3)

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