Area of a trapezoid
solve for b1: A= 1/2h(b1= b2)
Looks like a typo
A = (1/2) h (B1+B2)
2 A = h B1 + h B2
h B1 = 2 A - h B2
B1 = (2 A - h B2) / h
Next time try to write it in the correct format ok ty :)
To solve for the base of a trapezoid (b1), given the area (A), height (h), and the fact that the two bases are equal (b1 = b2), you can follow these steps:
Step 1: Recall the formula for the area of a trapezoid, which is A = (1/2)h(b1 + b2). Since b1 = b2, the formula can be simplified to A = (1/2)h(2b), where b represents both bases.
Step 2: Multiply both sides of the equation by 2 to get rid of the fraction: 2A = h(2b).
Step 3: Divide both sides of the equation by h to isolate b: (2A)/h = 2b.
Step 4: Simplify the equation: b = (2A)/h.
So, to find the value of b1, you can substitute the given values of A and h into the equation b = (2A)/h.