math

use intermediate value theorem to show f(x) has a zero
f(x)= x^5 - 4x^4- 7x^2 - 6x; [-0.7, -0.6]

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  1. f(-0.7)=-0.7^5-4(-0.7^4)-7(-0.7^2)-6(-0.7) = -.35847

    f(-0.6)= substitue -0.6 in the equation = .48384

    Assuming that f(x)= x^5 - 4x^4- 7x^2 - 6x = 0

    Then solution would be
    -.35847 < 0 < .48384

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