Find the length of a side of a square whose perimeter and
area have the same value.
perimeter of a square is P=4s & the area of a square is A=s^2
so you know
s^2 = 4s
s^2 - 4s = 0
s(s-4) = 0
s = 0 or s=4
So the side is 4 units
area = 4^2 = 16
per. = 4(4) = 16posted by Reiny
Why did you stop? You were on the right track but forgot to make use of the most important piece of information given.
The perimeter of a square of side "s" is P=4s.
The area of the same square is A = s^2.
Find the length of a side of a square whose perimeter and area have the same value.
P = A = 4s = s^2
Can you take it from here?
posted by tchrwill