Physics

Two planes approach each other head-on. Each has a speed of 765 km/h, and they spot each other when they are initially 11.0 km apart. How much time do the pilots have to take evasive action?

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  1. Since they are traveling at the same speed, each plane has the same amount of time and distance to take evasive action.

    d = Vt,
    t = d / V = (11/2) / 765 = 0.0072s.

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  2. x=x0 + v0t +0.5at^2
    Acceleration is zero in the x direction

    My numbers are 800km/hr and 10.5 km
    Divide the distance between the planes by two since traveling at same speed
    0= 5.2 + 800t
    Solve for t
    t=23.4 seconds

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  3. Two planes approach each other head-on. Each has a speed of 760 km/h
    k
    m
    /
    h
    , and they spot each other when they are initially 12.3 km
    k
    m
    apart.

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