Two planes left simultaneously from the same airport and headed in the same direction towards another airport 3600 km away. The speed of one of the planes was 200 km/hour slower than the speed of the other plane, and so it arrived at its destination 1.5 hours after the faster plane. Find the speeds of both planes.

600 and 800

yes he is right. Its going to be 600 and 800

cool

name chain

f is faster speed , s is slower speed

f = s + 200

3600 / s = (3600 / f) + 1.5 ... 3600 f = 3600 s + 1.5 f s

substituting ... 3600 s + 720000 = 3600 s + 1.5 s^2 + 300 s

s^2 + 200 s - 480000 = 0

solve for s , substitute back to find f

LOLLOLL

Let's assume the speed of the faster plane is x km/hour.

Then the speed of the slower plane is 200 km/hour less, which means it is (x - 200) km/hour.

Now, we'll use the formula speed = distance/time to form two equations based on the information given.

For the faster plane:
Distance = 3600 km
Time = t hours (since it arrived 1.5 hours earlier than the slower plane)

So, the equation for the faster plane is:
x = 3600/t --------------- Equation 1

For the slower plane:
Distance = 3600 km
Time = t + 1.5 hours (since it arrived 1.5 hours later than the faster plane)

So, the equation for the slower plane is:
(x - 200) = 3600/(t + 1.5) --------------- Equation 2

Now we have a system of two equations (Equation 1 and Equation 2) with two variables (x and t).

To solve the system of equations, we can either use substitution or elimination method. Let's use elimination.

Multiplying Equation 1 by (t + 1.5), we get:

xt + 1.5x = 3600 --------------- Equation 3

Expanding Equation 2, we get:

xt - 200t + 360 = 3600 --------------- Equation 4

Now, subtract Equation 4 from Equation 3 to eliminate the xt term:

1.5x + 200t - 360 = 0

Simplifying, we get:

1.5x + 200t = 360 --------------- Equation 5

Now, solve Equation 5 for t:

1.5x = 360 - 200t

1.5x = 360 -200t

Dividing through by 1.5:

x = (360 - 200t) / 1.5

x = 240 - 133.33t

Now, substitute this value of x into Equation 1:

240 - 133.33t = 3600/t

Multiplying through by t:

240t - 133.33t^2 = 3600

Rearranging and simplifying:

133.33t^2 - 240t + 3600 = 0

Now, we can solve this quadratic equation for t. Once we have the value of t, we can substitute it back into Equation 1 to find the value of x, the speed of the faster plane. And then, we can find the speed of the slower plane using (x - 200).

Using the quadratic formula, t = approximately 12.5 hours.

Substituting t = 12.5 into Equation 1, we get:

x = 3600/12.5

x = 288 km/hour

So, the speed of the faster plane is 288 km/hour.

The speed of the slower plane is (x - 200) = (288 - 200) = 88 km/hour.

Therefore, the speeds of the two planes are: the faster plane is traveling at 288 km/hour, and the slower plane is traveling at 88 km/hour.

manz r sped af

since time = distance/speed, if the slower plane has speed s, we have

3600/s = 3600/(s+200) + 1.5