# calculus

How do you determine the limit without substitution. ie. lim x--> -2 sqr(x-2)

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1. lim sqrt(x-2) as x>-2?

there is no issue here, the limit is sqrt(-4) or 2i

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bobpursley
2. But you can't find the square root of negative 4. I need to use another alternative besides substituting

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3. I don't see the issue here.

If you wanted to use an infinite series for sqrt, you could use a binomial expansion for (x+a)^k but I wouldn't want to spend weeks on it.

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bobpursley

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