Math

How would you solve for X if X was the hypotenuse of a 45-45-90 triangle and the other two sides were Square Root of 11?

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  1. Use Pythagoras theorem:

    hypotenuse² = side1²+side2²l
    =(√11)²+(√11)²
    = 11 + 11
    = 22
    Therefore
    hypotenuse = √22

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  2. Thank you very much! I thought it was 2 Square Roots of 11. You saved me.

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  3. The method I have shown above is more general, and applies to any right-triangle.

    For a 45-45-90 triangle, you were close with the answer. A short-cut would be to multiply each side by √2, which makes:
    √2 * √11
    =√22.

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