A stone falls from a ledge and takes 8 seconds to hit the ground. The stone has an original velocity od 0/ms. How tall is the ledge?
h=1/2 g t^2
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A stone falls from a ledge and takes 8 seconds to hit the ground. The stone has an original velocity of 0 m/s. How tall is the ledge?
313.6
To find the height of the ledge, we can use the formula for the distance an object falls due to gravity:
d = (1/2) * g * t^2
Where:
d is the distance (height)
g is the acceleration due to gravity (approximately 9.8 m/s^2)
t is the time taken for the stone to fall (8 seconds in this case)
Plugging in the values:
d = (1/2) * 9.8 m/s^2 * (8 s)^2
d = (1/2) * 9.8 m/s^2 * 64 s^2
d = 4.9 m/s^2 * 64 s^2
d = 313.6 meters
Therefore, the height of the ledge is approximately 313.6 meters.