The net external force on the propeller of a 3.6 kg model airplane is 8.4 N forward.
What is the acceleration of the airplane?
Answer in units of m/s
2
8.4 = 3.6 a
so
a = 8.4/3.6
IF the airplane is stopped and there is no drag on the airplane surfaces due to the propeller wake and there is no friction between the plane and the runway
To find the acceleration of the airplane, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
The formula for Newton's second law is:
F = ma
Where:
F is the net force acting on the object,
m is the mass of the object,
a is the acceleration of the object.
In this case, the net force acting on the propeller of the airplane is given as 8.4 N forward, and the mass of the airplane is 3.6 kg.
Substituting the given values into the equation, we can solve for acceleration:
8.4 N = 3.6 kg * a
Divide both sides of the equation by 3.6 kg to isolate the variable a:
a = 8.4 N / 3.6 kg
Calculating this, we get:
a = 2.33 m/s^2
Therefore, the acceleration of the airplane is 2.33 m/s^2.