Math

The length of a rectangle is 5 cm greater than it width. The perimeter is 58 cm. What are the dimension of the rectangle?

I know the formula for Triangle Perimeter is 2(L+W) and the L is +5 more than the W but I can't write the equation for it. This is what I was thinking 58= 4x-5
Thanks again.

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  1. 2(x+(x+5))=58
    2(2x+5)=58
    4x+10=58
    then subtract 10 from both side, which gives you,
    4x=48
    here x=12 and the length is x+5 which is 12+5=17
    L:17 and B:12

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  2. perimeter=2(l+W)=2(w+5+w)

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    bobpursley

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