math

Evaluate each factorial expression.

106!
104!

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asked by marie
  1. There is no exact way to evaluate factorials except to calculate them by multiplication:

    They turn out to be:
    104!=102990167451456276238485838647650442830537724549990721823254917768878717324
    75287174542709871683888003235965704141638377695179741979175588724736000000000000
    000000000000
    =1.0299016745145628*10^166 (approx.)

    and

    106!=114628056373470835453434738414834942870388487424139673389282723476762012382
    44994625266036087184167347601629828709643514374735052822822430250631168000000000
    0000000000000000
    =1.1462805637347084*10^170 (approx.)

    If only an approximation is required, Stirling's approximation could be used for large factorials (n>100):
    n! ~ sqrt(2πn)(n/e)^n
    where the error is of the order 1/n.

    A closer approximation can be obtained by summing the series:
    n! ~ sqrt(2πn)(n/e)^n(1+1/(12n)+1/(288n²)-139/(51840n³)-...)

    For more information, see:
    http://en.wikipedia.org/wiki/Stirling%27s_approximation

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