How much work is done when a mass of 30N is lifted vertically through 6m
Work = Fd = 30N * 6m = 180 Joules.
W is equal to force *displacement
Therefore
30N*6m is equal to 180Nm
To calculate the work done when lifting an object vertically, you can use the formula:
Work = Force * Distance * cos(theta)
In this case, the force is the weight of the object, which is equal to the mass multiplied by the acceleration due to gravity (9.8 m/s^2). The distance is given as 6m, and theta represents the angle between the force vector and the direction of displacement, which in this case is 0 degrees since the force and displacement are in the same direction. Therefore, cos(theta) equals 1.
Let's calculate the work done:
Weight = mass * acceleration due to gravity
Weight = 30N
Work = Weight * Distance * cos(theta)
Work = 30N * 6m * 1
Work = 180 Joules
So, the work done when lifting a mass of 30N vertically through 6m is 180 Joules.