math.

A theater purchases \$500 worth of Sticky Bears and chocolate bombs. Each bag of Sticky Bears costs \$1.50 and each bag of Chocolate Bombs costs \$1.00. If a total of 400 bags of candy were purchased, how many bags of Chocolate Bombs did the theater buy?

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1. Let
S=number of bags of sticky bears, then
400-S=number of bags of chocolate bombs.

From total cost = \$500, we get
1.5S+1.0(400-S)=500
Solve for S
0.5S = 500-400
S=200

Quick way:
each bag of sticky bears costs 1.50
each bag of chocolate costs 1.00
Average cost = \$500/400=1.25
which is smack in between 1.00 and 1.50.
So equal number of bags of each, namely 200.

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posted by MathMate

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