The radius of the Earth is 6.38 x(10^6)m. How far (path length) does a point on the equator move if the Earth rotates...
a.
20 degrees
b.
20 radians
c.
20 revolutions
Assume this: The Earth rotates exactly around N and S poles, Earth is perfect sphere, and do not count the Earth's orbit around the sun.
HINT: Ө = d/r, where Ө is in radians...and circumference = 2πr
Help me find c.
Charlie and John -- and a few others -- you are all using the same computer -- and appearing to be the same person who is talking to himself.
Please don't confuse us with multiple user names.
Ms. Sue is correct. The games you're playing are a good way to get yourself banned.
To determine how far a point on the equator moves if the Earth rotates, we need to calculate the distance based on the given angles of rotation.
a. 20 degrees:
To calculate the distance traveled on the equator when the Earth rotates by 20 degrees, we need to calculate the circumference of a circle with a radius equal to the radius of the Earth. The formula for the circumference of a circle is 2πr, where r is the radius.
So, the distance traveled would be:
Distance = (20/360) * 2π * 6.38 x 10^6 m
b. 20 radians:
To calculate the distance traveled on the equator when the Earth rotates by 20 radians, we use the formula Distance = angle * radius.
So, the distance traveled would be:
Distance = 20 * 6.38 x 10^6 m
c. 20 revolutions:
To calculate the distance traveled on the equator when the Earth completes 20 revolutions, we need to calculate the circumference of the Earth and multiply it by the number of revolutions.
The distance traveled would be:
Distance = 2π * 6.38 x 10^6 m * 20
Therefore:
a. The point on the equator moves a distance of (20/360) * 2π * 6.38 x 10^6 meters when the Earth rotates by 20 degrees.
b. The point on the equator moves a distance of 20 * 6.38 x 10^6 meters when the Earth rotates by 20 radians.
c. The point on the equator moves a distance of 2π * 6.38 x 10^6 m * 20 meters when the Earth completes 20 revolutions.