4 FeS(s) + 7 O2(g) ==> 2 Fe2O3(s) + 4 SO2(g)
7.82 moles of FeS are required to produce 3.91 moles of Fe2O3
What is the maximum number of liters of Fe2O3(s) that can be made from 10.95 L of O2(g) and 18.64 L of FeS(s) at STP?
The problem here is "liters" of Fe2O3? and Liters of FeS? These are not gases, and something is wrong....
To find the maximum number of liters of Fe2O3 that can be made, we need to determine the limiting reactant in the given reaction. The limiting reactant is the reactant that is completely consumed and determines the maximum amount of product that can be formed.
To solve this, we first need to convert the given volumes of O2 and FeS to moles at STP (Standard Temperature and Pressure).
At STP, 1 mole of any gas occupies a volume of 22.4 liters. Therefore, we can use the following conversions:
1 mole O2 = 22.4 liters O2
1 mole FeS = 22.4 liters FeS
Using these conversion factors, we can calculate the moles of O2 and FeS:
Moles of O2 = 10.95 L of O2 * (1 mole O2 / 22.4 L O2) = 0.489 mole O2
Moles of FeS = 18.64 L of FeS * (1 mole FeS / 22.4 L FeS) = 0.833 mole FeS
Now we need to compare the moles of FeS and O2 to see which is the limiting reactant. The balanced equation indicates that the molar ratio between FeS and Fe2O3 is 4:2, or 2:1. Therefore, we need half the number of moles of FeS to produce the same number of moles of Fe2O3.
Moles of Fe2O3 = 0.833 mole FeS * (1 mole Fe2O3 / 2 moles FeS) = 0.4165 mole Fe2O3
Since the balanced equation shows that the molar ratio between O2 and Fe2O3 is 7:2, or 3.5:1, we can calculate the theoretical yield of Fe2O3 using the moles of O2:
Moles of Fe2O3 = 0.489 mole O2 * (1 mole Fe2O3 / 3.5 moles O2) = 0.1397 mole Fe2O3
Based on the stoichiometry of the reaction, the limiting reactant is FeS because it produces the least amount of Fe2O3. Therefore, FeS is the reactant that will determine the maximum number of liters of Fe2O3 that can be produced.
To convert the moles of Fe2O3 to liters at STP, we can use the following conversion factor:
1 mole Fe2O3 = 22.4 liters Fe2O3
Liters of Fe2O3 = 0.4165 mole Fe2O3 * (22.4 liters Fe2O3 / 1 mole Fe2O3) = 9.32 liters Fe2O3
Therefore, the maximum number of liters of Fe2O3 that can be made from 10.95 L of O2(g) and 18.64 L of FeS(s) at STP is 9.32 liters.