physics

If velocity v of particle moving in straight line is related with distance travelled S as v=2(1+S)^1/2. What will the acceleration of the particle?

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asked by Pappi
  1. The problem I have here is units.

    velocity is distance/time, and your equation is sqrt distance. Hmmmm.

    Assuming somehow that is fixed in magic land, then

    acceleration= dv/dt=
    (1+s)^-1/2 * ds/dt but ds/dt is V so

    acceleration= 2 (1+s)^0=2

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