Determine the average rate of change of B from t=0s to t=352s.
A to 2B
Time Concentration of A (M)
0 0.670
176 0.385
352 0.100
Just like any other average.
(A) changed from 0.670 to 0.100 or 0.570 M. That change took 352 sec; therefore, 0.570/352 = ??
http://www.chem.purdue.edu/gchelp/howtosolveit/Kinetics/CalculatingRates.html#AvgRate
To determine the average rate of change of B from t=0s to t=352s, we need to find the change in concentration of B and the change in time over this interval.
First, let's calculate the concentration of B at each time point using the given relation A to 2B:
At t=0s, B = (1/2) * 0.670 = 0.335
At t=176s, B = (1/2) * 0.385 = 0.1925
At t=352s, B = (1/2) * 0.100 = 0.05
Now, we can calculate the change in concentration of B over the interval:
Change in B concentration = 0.05 - 0.335 = -0.285
Next, let's calculate the change in time:
Change in time = 352s - 0s = 352s
Finally, we can calculate the average rate of change of B:
Average rate of change of B = (Change in B concentration) / (Change in time)
Average rate of change of B = -0.285 / 352s ≈ -0.0008102 M/s
Therefore, the average rate of change of B from t=0s to t=352s is approximately -0.0008102 M/s.
To determine the average rate of change of B from t=0s to t=352s, we need to find the change in concentration of B during that time interval and divide it by the change in time.
First, let's determine the concentration of B at t=0s and t=352s. Since the reaction A to 2B is happening, we can use the stoichiometry of the reaction to find the concentration of B.
At t=0s, the concentration of A is 0.670 M, and the stoichiometry of the reaction tells us that every 1 molecule of A reacts to produce 2 molecules of B. Therefore, the concentration of B at t=0s is 2 times the concentration of A, which is 2 * 0.670 M = 1.340 M.
Similarly, at t=352s, the concentration of A is 0.100 M, and applying the stoichiometry, the concentration of B at t=352s is 2 * 0.100 M = 0.200 M.
The change in concentration of B during the time interval from t=0s to t=352s is the difference between the concentration at t=352s and t=0s: 0.200 M - 1.340 M = -1.140 M.
The change in time is t=352s - t=0s = 352s.
Now, we can calculate the average rate of change of B by dividing the change in concentration by the change in time:
Average rate of change of B = (change in concentration of B) / (change in time)
= (-1.140 M) / (352s)
Thus, the average rate of change of B from t=0s to t=352s is approximately -0.0032 M/s.