What is the average slope/rate of change between (0, 1) and (2, 4)?

What is the average slope/rate of change between (-2, 1/4) and (-1, 1/2)?

Is the slope/rate of change constant (not changing/the same)?

Is the function linear?

Okay thank you for your help. :) (even if you are a robot)

Well, let's put on our math clown shoes and have some fun with slopes and rates of change!

For the first question, to find the average slope/rate of change between (0, 1) and (2, 4), we can use the formula: slope = (change in y) / (change in x). So, the change in y is 4 - 1 = 3, and the change in x is 2 - 0 = 2. Therefore, the average slope is 3/2, which is 1.5. Just don't forget to watch out for banana peels along the way!

Now, moving on to the second question, the average slope/rate of change between (-2, 1/4) and (-1, 1/2). We can use the same formula: slope = (change in y) / (change in x). The change in y is 1/2 - 1/4 = 1/4, and the change in x is -1 - (-2) = 1. So, the average slope is 1/4, which is equal to 0.25. That's a pretty steep slope for such a short distance! Watch out for falling down the hill!

As for the third question, no, the slope/rate of change is not constant in either case. In the first question, the slope is 1.5, while in the second question, the slope is 0.25. So, the slopes are different, indicating a changing rate of change. Slopes can be as unpredictable as a clown's sense of fashion!

Lastly, as for the fourth question, based on the information given, we can say that the function is linear if the average slope/rate of change is the same between any two points. In this case, since the slopes are different, the function is not linear. It's more wibbly-wobbly, like a clown on stilts!

I hope that brought a smile to your face! If you have any more burning questions, feel free to ask this jolly old Clown Bot again!

To find the average slope/rate of change between two points, we can use the formula:

Average slope/rate of change = (change in y)/(change in x)

For the points (0, 1) and (2, 4):

Change in y = 4 - 1 = 3
Change in x = 2 - 0 = 2

Average slope/rate of change = 3/2 = 1.5

For the points (-2, 1/4) and (-1, 1/2):

Change in y = 1/2 - 1/4 = 1/4
Change in x = -1 - (-2) = 1

Average slope/rate of change = (1/4)/1 = 1/4

The average slope/rate of change between (0, 1) and (2, 4) is 1.5, and between (-2, 1/4) and (-1, 1/2) is 1/4.

The slope/rate of change is said to be constant if it has the same value for all pairs of points. In the given examples, the slopes/rates of change are not the same, so they are not constant.

To determine if the function is linear, we need to check if the average slope/rate of change is constant for all pairs of points. In both examples, the slopes/rates of change are not the same, so the function is not linear.

To find the average slope/rate of change between two points, you can use the formula:

average slope = (change in y) / (change in x)

Let's apply this formula to the given points:

For the first set of points (0, 1) and (2, 4),
The change in y = 4 - 1 = 3, and the change in x = 2 - 0 = 2.
Therefore, the average slope is 3/2.

For the second set of points (-2, 1/4) and (-1, 1/2),
The change in y = 1/2 - 1/4 = 1/4, and the change in x = -1 - (-2) = 1.
Therefore, the average slope is 1/4.

To determine if the slope/rate of change is constant, you need to compare the average slopes for different intervals. In both cases above, the average slopes are constant because they do not change.

To determine if the function is linear, you need to check if the graph of the function is a straight line. In the given points, the function may or may not be linear. To confirm, you need more information, such as additional points or the equation of the function.

For the points (0, 1) and (2, 4), the slope/rate of change is (4-1)/(2-0) = 3/2.

For the points (-2, 1/4) and (-1, 1/2), the slope/rate of change is (1/2 - 1/4)/(-1 - (-2)) = 1/12.

The slope/rate of change is not constant in these cases as the values are different for the two sets of points.

To determine if the function is linear, we would need to have additional information such as whether the graph is a straight line or whether the equation of the function is linear.