The rate of the following reaction is 0.480 M/s. What is the relative rate of change of each species in the reaction?
A+3B=2C
-rate A = -1/3 B = 1/2 C.
Is that what you mean by "relative"?
That means if A is disappearing at the rate of 0.480 M, then B is disappearing at the rate of 3*0.480M and C is appearing at the rate of 2*0.480M.
Determine the average rate of change of B from t=0s to t=352s.
A to 2B
Time Concentration of A (M)
0 0.670
176 0.385
352 0.100
0.0037
To determine the relative rate of change of each species in the reaction, we need to calculate the rate of change for each species in terms of their stoichiometric coefficients.
The balanced equation for the reaction is:
A + 3B → 2C
Based on this equation, we can conclude that the rate of change of species A is (-1/2) times the rate of change of species C. Similarly, the rate of change of species B is (-1/3) times the rate of change of species C.
Given that the rate of the reaction is 0.480 M/s, we can calculate the relative rate of change for each species as follows:
Relative rate of change of species A = (-1/2) * rate of change of species C
Relative rate of change of species A = (-1/2) * 0.480 M/s
Relative rate of change of species B = (-1/3) * rate of change of species C
Relative rate of change of species B = (-1/3) * 0.480 M/s
This will give you the relative rate of change of each species in the reaction.