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how do you solve 7(3x+4)=8(2x+5)+13 expand the parenthesis...I will do the left side.. 21x + 29= Now, subtract sixteen x from both sides, and subtract 28 from both sides. I will be happy to check your work. 7(3x+4)=8(2x+5)+13 21x
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7(3x+4)=8(2x+5)+13 how would I start a equation like this would it be 21x+28=16x+40+13 ? Yes, that is the way to start. Now collect the x's on one side. so it would be 21x21x=28= 28=5+40+13 28+13=41 x=41 7(3x+4)=8(2x+5)+13
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find the domains of the following functions: a) f(x)=x^20 b) g(x)=1/(x3) c) h(x)=1/(4x^2=21x18) d) k(x)=sqrt (4x^221x18) e) p(x)=1/sqrt(4x^221x18)
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This problem makes no sence to me i tried it but i know i am completely wrong someone please help. The cost for a longdistance telephone call is $0.36 for the first minute and $0.21 for each additional minute or portion thereof.
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*simplify by combining like terms, if possible. then, remove the GCF and factor fully. 2x^221x+36+x^2 =3x^221x+36 ...i'm not sure what to do after that, could you help and show the steps please
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Domain of a) x^20 b) 1/(x3) c)1/(4x^221x18) d) sqrt(4x^221x18) e) 1/ sqrt(4x^221x18)
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7/x+5/3x=2/x5 so lcm=3x(x5) 21(x5)+5(x5)=5x 21x105+5x25=5x 26x130=5x 26x to both sides 130=21x divide each side by 21 130/21 x=6.19 is this correct thanks for checking my work.
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