chemistry

when 400g of a 20% sol. by weight was cooled ,50g of solute percipited .the percentage concentration of remaining solution

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  1. initially, 80 grams was in solution, at the end, 30 grams remained in a solutioin of 350grams.

    percent=30/350 * 100

  2. 8.6 %

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  3. First 400 GM of solution is given in which 20% is tha molecular weight of solute and 80 % molecular weight of solvent .

    Now 20% of 400 GM of solution is 80 GM .
    Weight of solute precipitated is 50gm.
    Now amount of solute left in solution is 80-50= 30 GM.
    And amount of solution left is 400-50= 350gm.
    Now new concentration is 30/350 *100% = 8.6%

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    posted by Dheeraj
  4. 8.57

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