if [OH-]=10-pOH. NAd the pOH=7.85 then what does [OH-]equal?
pOH = 7.85
- log(OH^-) = 7.85
(OH^-) = 1.41 x 10^-8
Do you know how to do this on your calculator. Enter 7.85 on the calculator, hit the change sign (or if your calculator doesn't have a changr sign, enter -7.85), then hit the 10x button.
thank you so much
you simplified it for me perfectly.
To find the concentration of hydroxide ions ([OH-]) when the pOH is given, you can use the relationship:
pOH = -log[OH-]
First, rearrange the equation to isolate [OH-]:
-log[OH-] = pOH
Now, take the antilog (inverse log) of both sides of the equation:
[OH-] = 10^-pOH
Substitute the given pOH value of 7.85 into the equation:
[OH-] = 10^(-7.85)
Now, calculate the value of 10^(-7.85) using a scientific calculator:
[OH-] ≈ 1.74 x 10^(-8)
Therefore, the concentration of hydroxide ions [OH-] is approximately 1.74 x 10^(-8) M.