if a 5microfarad capacitor is charged by a 20volts battery and it is then connected across an uncharged 20microfarad capacitor , find the potential energy

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  1. Find the PE of what?

  2. 5*10^-6 = Q/20
    Q = 10^-4

    That charge is distributed on the new capacitance of C = (5+20)10^-6 = 25 *10^-6

    V = Q/C
    V = 10^-4/(25*10^-6) = 10^2/25 = 4 Volts

    Energy = (1/2) Q V = .5 *10^-4 * 4
    = 2*10^-4 Joules

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