As part of a fundraising effort, a group of students decide to sell chocolate bars from door to door. They sold moro bars at three-quaters of the houses they tried, scrunch bars at two-thirds of their calls, and at 10 houses they sold both how many houses did they visit?22
Annabella, I don't believe you have provided enough info to solve your candy bar fundraiser problem.
To find out how many houses the students visited, we can use the information provided in the problem.
Let's assume the total number of houses the students visited as 'x.'
According to the problem statement:
- They sold Moro bars at three-quarters of the houses they tried, which means they sold Moro bars at 3/4 * x houses.
- They sold Scrunch bars at two-thirds of their calls, so they sold Scrunch bars at 2/3 * x houses.
- They sold both Moro and Scrunch bars at 10 houses.
To find the total number of houses they visited, we need to add the houses where they sold Moro bars, Scrunch bars, and both together.
Total houses visited = Moro bars + Scrunch bars - Both
Given that both Moro bars and Scrunch bars sold at 10 houses:
Total houses visited = (3/4 * x) + (2/3 * x) - 10
As per the problem, the students visited 22 houses:
22 = (3/4 * x) + (2/3 * x) - 10
Now, we can solve this equation to find the value of 'x':
22 + 10 = (3/4 * x) + (2/3 * x)
32 = (9/12 * x) + (8/12 * x)
32 = (17/12 * x)
To isolate 'x', we can multiply both sides of the equation by 12/17:
32 * (12/17) = x
(32 * 12)/ 17 = x
(384/17) = x
Therefore, the students visited approximately 22.59 houses. Since they cannot visit a fraction of a house, we can round it to the nearest whole number.
Hence, the students visited around 23 houses.