# Maths

Find the two digit number such that if you treble it and you take away four times the reverse of that number, the ansswer will be 8.

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and the reverse is 10B+A

using the information in the question

3(10A+B)-4(10B+A)=8

26A-37B=8

Now neither A or B can be zero (0A or 0B is not a valid number)

also we can say that if B>=A then the result is negative.

We can from the equation infer that A is only slightly larger than B

So I tred
A=5 B=3
A=6 B=4
A=7 B=5

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