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A car with good tires on a dry road can decelerate at about 5.0m/s/s when braking. If the car is traveling at 55miles/hour, how much time does it take the car to stop? 55 mph = 80.7 ft/s = 24.6 m/s Divide the initial speed by the 
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A car with good tires on a dry road can decelerate at about 5 m/s^2 when breaking. Suppose a car is initially traveling at 65 mph. What is the stopping distance?(give answer in meters and in feet) I changed 65mph into 29.05m/s. so 
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1. a car traveling on a dry road with a velocity of +32.0m/s. The driver slams on the breaks and skids to a halt with an acceleration of 8.00m/s^2. on an icy road the car would have skidded to a halt with an acceleration of 
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6. A car is moving along a straight road at 60 mph [26.7 meter/sec ]. The driver makes slams on his breaks locking them so that the car skid s to a stop. Assume a constant braking force due to friction , and a kinetic friction 
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1) A car moving along a straight stretch of road at 60 mph [26.7 meters/sec]. The driver makes slams on his breaks locking them so that the car skids to a stop. Assume a constant braking force due to friction, and a kinetic 
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The driver of a car on a horizontal road makes an emergency stop by applying the brakes so that all four wheels lock and skid along the road. The coefficient of kinetic friction between tires and road is 0.39. The separation 
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On a dry road, a car with good tires may be able to brake with a constant deceleration of 3.31 m/s2. (a) How long does such a car, initially traveling at 28.2 m/s, take to stop? (b) How far does it travel in this time? 
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On a dry road, a car with good tires may be able to brake with a constant deceleration of 4.17 m/s2. (a) How long does such a car, initially traveling at 22.4 m/s, take to stop? (b) How far does it travel in this time? 
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If a car is traveling downhill at 45 miles per hour on dry pavement, then the braking distance B is B = 45/(0.4+m), where m 
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The tires of a car make 58 revolutions as the car reduces its speed uniformly from 92 to 33 . The tires have a diameter of 0.86 . What was the angular acceleration of the tires? If the car continues to decelerate at this rate, how