How many grams of saline are needed to make 300 ml of 0.9%(w/v) saline?
What is .09*300?
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To find out how many grams of saline are needed to make 300 ml of 0.9% (w/v) saline, we need to determine the mass of saline in grams that corresponds to the given percentage.
First, let's understand the term "0.9% (w/v)." This refers to a solution where the solute (saline) is expressed as a weight/volume percentage. It means that the weight of the solute (in grams) is 0.9% of the total volume of the solution (in milliliters).
To calculate the mass of solute required, we can use the formula:
Mass of solute (g) = (Percentage concentration / 100) x Volume of solution (ml)
Now, let's plug in the values:
Percentage concentration = 0.9%
Volume of solution = 300 ml
Mass of solute (g) = (0.9 / 100) x 300
Calculating this expression, we get:
Mass of solute (g) = (0.009) x 300
Mass of solute (g) = 2.7 grams
Therefore, to make 300 ml of 0.9% (w/v) saline, you will need 2.7 grams of saline.