Write the equation of a circle with a center at (2.5, –3.5) and a radius of 1.2.
Yes, this is easy. What is the answer?
(x-a)^2+(y-b)^2=r^2
Are you having difficulty, or are you answer grazing?
Difficultly by far! I am taking a 200 question test (which after completed I will graduate high school!) and im down to the last 15 questions-I cannot remember for the life of me how to do these!
To write the equation of a circle with a center at (h, k) and a radius r, you can use the following formula:
(x - h)^2 + (y - k)^2 = r^2
In this case, the center of the circle is (2.5, -3.5), and the radius is 1.2. Plugging these values into the equation, we get:
(x - 2.5)^2 + (y - (-3.5))^2 = 1.2^2
Simplifying further, we have:
(x - 2.5)^2 + (y + 3.5)^2 = 1.44
Therefore, the equation of the circle with a center at (2.5, -3.5) and a radius of 1.2 is:
(x - 2.5)^2 + (y + 3.5)^2 = 1.44