any help would be great
The sum of 2 consecutive integers is equal to their difference.
Let the two consecutive numbers be x and x+1
translating "The sum of 2 consecutive integers is equal to their difference" ---> x + x+1 = x+1 - x
I trust you to solve for x
x + x + 1 = x + 1 - x
-x + x + x + 1 = x + 1 -x + -x
= x + 1 = x + 1 = 2x
x = 1 = 1 = x + 1 -1 - 2x
x = x = 2x
3 = 3 - 2 * 3 = [-3]
x + x + 1 = x + 1 = x
x + x + x + 1 = x + 1 - x + x
3x + 1 = x + 1
-x + 3x + 1 = -x + x + 1
2x + 1
To solve this problem, let's consider two consecutive integers. Let's call the first integer x, and the second integer (which follows the first one) x+1.
We know that the sum of these two consecutive integers is equal to their difference. Mathematically, we can express this as:
x + (x+1) = (x+1) - x
Now, let's simplify this equation:
x + x + 1 = x + 1 - x
Combining like terms:
2x + 1 = 1
Next, let's isolate the variable x:
2x = 0
Now divide by 2:
x = 0/2
Thus, we have found that the first integer, x, is equal to 0.
Now we can find the second integer by adding 1 to x:
x + 1 = 0 + 1
Therefore, the first consecutive integer is 0, and the second consecutive integer is 1.
So, the two consecutive integers that satisfy the condition are 0 and 1.