How many oxygen atoms are in 5.23 g of C6H12O6
There are 6.022E23 molecules C6H12O6 in 1 mole (180 g); therefore, in 5.23 there will be
6.022E23 x (5.23/180) = ?? molecules
Then there are 6 atoms of O in 1 molecule so atoms O will be 6 times ?? molecules.
1.749*10^22
I have no idea
No idea
Well, let's break it down. C6H12O6 is the molecular formula for glucose. In glucose, there are 6 oxygen atoms. So, if we have 5.23 g of glucose, we can calculate the number of moles of glucose using its molar mass, which is about 180.16 g/mol. Then, multiplying the number of moles by the Avogadro constant (6.02 x 10^23), we can determine the number of molecules of glucose. Finally, multiplying the number of molecules by 6 (since each molecule of glucose contains 6 oxygen atoms), we can find out the number of oxygen atoms in 5.23 g of glucose.
But you know what? Oxygen atoms are clingy. They always stick together in a relationship. So in the end, it doesn't matter how many there are, because they'll always be bonded together happily! So let's just say there are lots of oxygen atoms in 5.23 g of glucose and leave it at that. 😉
To determine the number of oxygen atoms in 5.23 g of C6H12O6, we need to use the concept of molar mass and stoichiometry.
1. Start by calculating the molar mass of C6H12O6:
C6H12O6 = 6(C) + 12(H) + 6(O)
= 72 g/mol + 12 g/mol + 96 g/mol
= 180 g/mol
2. Now, we need to convert the given mass (5.23 g) to moles. This can be done using the formula:
Moles = Mass / Molar mass
Moles = 5.23 g / 180 g/mol
Moles ≈ 0.029 moles
3. Next, we use the balanced chemical formula of C6H12O6 to determine the molar ratio of oxygen to C6H12O6. From the formula, we can see that there are 6 oxygen atoms in each C6H12O6 molecule.
1 mol of C6H12O6 = 6 moles of O
4. Finally, calculate the number of oxygen atoms:
Number of oxygen atoms = Moles of O in C6H12O6 × Avogadro's constant
Moles of O in C6H12O6 = Moles of C6H12O6 × 6
= 0.029 moles × 6
≈ 0.174 moles
Avogadro's constant = 6.022 × 10^23 atoms/mol
Number of oxygen atoms = 0.174 moles × 6.022 × 10^23 atoms/mol
≈ 1.05 × 10^23 oxygen atoms
Therefore, there are approximately 1.05 × 10^23 oxygen atoms in 5.23 g of C6H12O6.