math

find the volume of the cup. the diameter of the top is 3inches. the diameter of the base is 2inches. the height is 4inches.

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  1. If you draw a picture, and imagine that the truncated cone is produced to its vertex V where the diameter is zero, then
    height from V to the section at which the diameter is 2"
    = 2*4" = 8"

    Height of complete cone = 4"+8"=12"
    Height of "missing" cone = 8"

    Volume of complete cone
    = πr²h/3
    = 12π(3/2)²/3
    = 9π

    Volume of "missing" cone
    =πr²h/3
    =8π(2/2)²/3
    =(8/3)π

    Therefore volume of the truncated cone
    = 9π - (8/3)π
    = ...

    Volume of comp

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